\(\mathop {\lim }\limits_{x \to - \infty } \left( {x - {x^3} + 1} \right)\) bằng
A. 1 | B. | C. 0 | D. |
\(\mathop {\lim }\limits_{x \to - \infty } \left( {x - {x^3} + 1} \right) = \mathop {\lim }\limits_{x \to - \infty } {x^3}\left( { - 1 + \frac{1}{{{x^2}}} + \frac{1}{{{x^3}}}} \right) = + \infty \)
Chọn D.
-- Mod Toán 11