\(\mathop {\lim }\limits_{x \to 0} \frac{{{{(1 + x)}^3} - 1}}{x}\) bằng
A. 0 | B. 1 | C. 3 | D. |
\(\mathop {\lim }\limits_{x \to 0} \frac{{{{\left( {1 + x} \right)}^3} - 1}}{x} = \mathop {\lim }\limits_{x \to 0} \frac{{1 + 3x + 3{x^2} + {x^3} - 1}}{x} = \mathop {\lim }\limits_{x \to 0} \left( {3 + 3x + {x^2}} \right) = 3\)
Đáp án : C
-- Mod Toán 11