Giá trị sin 47π/6 là:
\(\begin{array}{l}
{\rm{A}}{\rm{.}}\frac{{\sqrt 3 }}{2}\\
{\rm{B}}{\rm{.}}\frac{1}{2}\\
{\rm{C}}{\rm{.}}\frac{{\sqrt 2 }}{2}\\
{\rm{D}}{\rm{. - }}\frac{1}{2}
\end{array}\)
Vì \(\frac{{47\pi }}{6} = \frac{{48\pi - \pi }}{6} = 8\pi - \frac{\pi }{6} \Rightarrow \sin \frac{{47\pi }}{6} = - \sin \frac{\pi }{6} = - \frac{1}{2}\)
-- Mod Toán 10